6x^2-125x+600=0

Solution for 6x^2-125x+600=0 equation:

6x^2-125x+600=0

a = 6; b = -125; c = +600;
Δ = b2-4ac
Δ = -1252-4·6·600
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-35}{2*6}=\frac{90}{12}
=7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+35}{2*6}=\frac{160}{12}
=13+1/3
$